If ΔABC is right angled at C, then the value of Sec (A+B) is ______.​

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If ΔABC is right angled at C, then the value of Sec (A+B) is ______.​

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2 thoughts on “If ΔABC is right angled at C, then the value of Sec (A+B) is ______.​”

  1. Answer:

    We know that the sum of all three angles of a triangle is always 180°. Given ∠C=90°, hence, ∠A+∠B=180°-90° =90°. We have to find the value of Sec(∠A+∠B)

    Step-by-step explanation:

    The triangle ABC is given, which is a right-angled triangle with ∠C  is equal to 90°.

    We know that the sum of all three angles of a triangle is always 180°.

    Hence, for ΔABC, ∠A+∠B+∠C =180°

    Given ∠C=90°, hence, ∠A+∠B=180°-90° =90°.

    We have to find the value of Sec(∠A+∠B).

    Hence, Sec(∠A+∠B) = Sec 90° =1/ Cos 90°=1/0=∞. {Since Cos 90°=0}

    Therefore, Sec(∠A+∠B)= ∞ (Answer)

    Dusra vala math sum nahi pata hai

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