an elevator descends into a mine shaft at the rate of 8 metre per minute. if the distant starts from 12 metre above the ground lev

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an elevator descends into a mine shaft at the rate of 8 metre per minute. if the distant starts from 12 metre above the ground level, how long will it take to reach – 468 m​

1 thought on “an elevator descends into a mine shaft at the rate of 8 metre per minute. if the distant starts from 12 metre above the ground lev”

  1. Consider the elevator starts from 12 meter above.

    The speed of elevator will be = 8m/min

    Dis to cover = 468 and + 12m

    = 490m

    So time = dis/speed

    = 490/8

    = 61.1 mins

    ~ 1hour and 1 min

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