an elevator descends into a mine shaft at the rate of 8 metre per minute. if the distant starts from 12 metre above the ground level, how long will it take to reach – 468 m About the author Luna

Consider the elevator starts from 12 meter above. The speed of elevator will be = 8m/min Dis to cover = 468 and + 12m = 490m So time = dis/speed = 490/8 = 61.1 mins ~ 1hour and 1 min Reply

Consider the elevator starts from 12 meter above.

The speed of elevator will be = 8m/min

Dis to cover = 468 and + 12m

= 490m

So time = dis/speed

= 490/8

= 61.1 mins

~ 1hour and 1 min