after four years the age of father is twice as old as hos son. five years before the father age was 1 years more than triple of his son. find their present ages

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Answer:

Step-by-step explanation:

x + 4 = 2y and x – 5 = 3y + 1. combining the equations we get x + 4 = 2y, x – 5 = 3y + 1

x = 2y – 4 and x = 3y + 6 adding 4 on both sides. x = 2y, x = 3y + 10 which means x = 10y where y represent ages. = 10 + 4 × 2 = 28 which means his father present age is 24 and his age is 10

Answer:

Step-by-step explanation:

x + 4 = 2y and x – 5 = 3y + 1. combining the equations we get x + 4 = 2y, x – 5 = 3y + 1

x = 2y – 4 and x = 3y + 6 adding 4 on both sides. x = 2y, x = 3y + 10 which means x = 10y where y represent ages. = 10 + 4 × 2 = 28 which means his father present age is 24 and his age is 10