water is flowing at the rate of 2.52 km/h through a cylindrical pipe into a cylindrical tank, the radius of the base is 40cm . if the increase in the level of water in the tank , in half an hour is 3.15m, find the internal diameter of the pipe.
હેલ્લો કેમ છો.. bored thai Gaya… તમારી પાસે ઈન્સ્ટાગ્રામ ટેલીગ્રામ એવું કાઈ હોઈ તો આપણે વાત કરી શકીએ.. otherwise you can also report for this irrelevant answer ..
Increase in the water level in half an hour = 3.1 5 m = 315 cm
Radius of the water tank = 40 cm
Volume of the water that falls in the tank in half an hour = πr²h = π(40)²(315) =504000π cm³
Rate of the water flow = 2.52 km/hr
Length of water column in half an hour = ((2.52×30)/60) km = 1.26 km = 126000 cm.
Let the internal diameter of the cylindrical pipe be d.
Volume of water that flows through the pipe in half an hour = π×(d/2)²×126000
By condition, π×(d/2)²×126000 =504000π
=> (d/2)² = 4 => d = 4
So, internal diameter of pipe = 4 cm
હેલ્લો કેમ છો.. bored thai Gaya… તમારી પાસે ઈન્સ્ટાગ્રામ ટેલીગ્રામ એવું કાઈ હોઈ તો આપણે વાત કરી શકીએ.. otherwise you can also report for this irrelevant answer ..
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