:-The upper
surface of a table is like trapezium. The length
of the parallel sides of this table is 7 m and 9 m
and

1 thought on “:-The upper<br />surface of a table is like trapezium. The length<br />of the parallel sides of this table is 7 m and 9 m<br />and”

1. Let′s understand the question.

   ★ This question says that the parallel sides measure 7 m and 9 m. The distance between the two parallel sides is 3 m. We have to find out the area of trapizum..!

   Let’s solve this problem..!

   [tex]\large\underline{\sf{Given- }}[/tex]

   A trapezium whose

   • length of parallel sides measure 7 m and 9m

   and

   • distance between two parallel sides is 3 m.

   [tex]\large\underline{\sf{To\:Find – }}[/tex]

   • Area of trapezium

   [tex]\large\underline{\sf{Solution-}}[/tex]

   Given that,

   • Length of one parallel side of trapezium = 7m

   • Length of other parallel side of trapezium = 9 m

   • Distance between two parallel sides = 3 m

   We know that

   [tex]\rm :\longmapsto\:Area_{(trapezium)} = \dfrac{1}{2} (sum \: of \parallel \: sides) \times distance \: beween \: them[/tex]

   [tex]\rm :\longmapsto\:Area_{(trapezium)} = \dfrac{1}{2} \times (9 + 7) \times 3[/tex]

   [tex]\rm :\longmapsto\:Area_{(trapezium)} = \dfrac{1}{2} \times 16 \times 3 [/tex]

   [tex]\bf\implies \:Area_{(trapezium)} = 24 \: {m}^{2} [/tex]

   Additional Information :-

   [tex] \boxed{ \bf \: Area_{(square)} = {(side)}^{2}} [/tex]

   [tex] \boxed{ \bf \: Area_{(rectangle)} = length \times breadth}[/tex]

   [tex] \boxed{ \bf \: Area_{(circle)} = \pi \: {r}^{2}} [/tex]

   [tex] \boxed{ \bf \: Area_{(rhombus)} = base \times height}[/tex]

   [tex] \boxed{ \bf \: Area_{(parallelogram)} = base \times height}[/tex]

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