The scores obtained by Alice in a quiz competition having 5 rounds is listed below. Positive points are
given for every corre

The scores obtained by Alice in a quiz competition having 5 rounds is listed below. Positive points are
given for every correct answer while negative points are given for every incorrect answer.
Rounds
Scores
Round 1
10
Round 2
– 20
Round 3
?
Round 4
40
Round 5
-5
Final Score
60
What was Alice’s score in Round 3?

About the author
Margaret

1 thought on “The scores obtained by Alice in a quiz competition having 5 rounds is listed below. Positive points are<br />given for every corre”

  1. [tex]\boxed{\large\textsf{${\large\textsf{L.S.A.}}_{\large\textsf{( \; Cuboid \; )}} = \large\textsf{2h ( l + b )}$}\\\\\large\textsf{${\large\textsf{T.S.A.}}_{\large\textsf{( \; Cuboid \; )}} = \large\textsf{2 ( lb + bh + hl )}$}\\\\\large\textsf{${\large\textsf{Volume}}_{\large\textsf{( \; Cuboid \; )}} = \large\textsf{l×b×h}$}\\\\\large\textsf{${\large\textsf{L.S.A.}}_{\large\textsf{( \; Cube \; )}} = \large\textsf{4×l²}$}\\\\\large\textsf{${\large\textsf{T.S.A.}}_{\large\textsf{( \; Cube \; )}} = \large\textsf{6 × l²}$}}[/tex]

    [tex]\large\textsf{${\large\textsf{Volume}}_{\large\textsf{( \; Cube \; )}} = \large\textsf{l²}$}[/tex]

    [tex]\large\textsf{${\large\textsf{C.S.A.}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{2 × πrh}$}[/tex]

    [tex]\large\textsf{${\large\textsf{T.S.A.}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{2πr × ( r + h )}$}[/tex]

    [tex]\large\textsf{${\large\textsf{Volume}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{πr²h}$}[/tex]

    [tex]\large\textsf{${\large\textsf{C.S.A.}}_{\large\textsf{( \; Cone \; )}} = \large\textsf{πrl}$}[/tex]

    [tex]\large\textsf{${\large\textsf{T.S.A.}}_{\large\textsf{( \; Cone \; )}} = \large\textsf{πr × ( r + l )}$}[/tex]

    [tex]\large\textsf{${\large\textsf{Volume}}_{\large\textsf{( \; Cone \; )}} $} \large\textsf{ =$\cfrac{\large\textsf{1}}{\large\textsf{3}}$}\large\textsf{× πr²h}[/tex]

    [tex]\large\textsf{${\large\textsf{T.S.A.}}_{\large\textsf{( \; Sphere \; )}} = \large\textsf{4πr²}$}[/tex]

    [tex]\large\textsf{${\large\textsf{Volume}}_{\large\textsf{( \; Sphere \; )}} $} \large\textsf{ =$\cfrac{\large\textsf{4}}{\large\textsf{3}}$}\large\textsf{× πr³}[/tex]

    Reply

Leave a Comment