The man is 3 times as old as his son . After 15 years, he will be only twice as old as his son . Find the present ages. About the author Margaret

Answer: 15 & 45 years Step-by-step explanation: Given: The man is 3 times as old as his son. Let the present age of son be x. The present age of the man = 3x Again, After 15 years, The age of the son = x+15 The age of the man = 3x+15 A/Q, 2×( The age of son) = The age of man => 2(x+15) = 3x+15 => 2x+30 = 3x+15 => 3x-2x = 30-15 x = 15 years. Therefore, The present age of son = 15 years The present age of man = 3x = 3× 15 = 45 years. Reply

Answer:15 & 45yearsStep-by-step explanation:Given:The man is 3 times as old as his son.Letthepresentageofsonbex.Thepresentageoftheman=3xAgain,After15years,Theageoftheson=x+15Theageoftheman=3x+15A/Q,2×(Theageofson)=Theageofman=>2(x+15)=3x+15=>2x+30=3x+15=>3x-2x=30-15x=15years.Therefore,Thepresentageofson=15yearsThepresentageofman=3x=3×15=45years.