The man is 3 times as old as his son . After 15 years, he will be only twice as old as his son . Find the present ages.

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Answer:15 & 45yearsStep-by-step explanation:Given:The man is 3 times as old as his son.Letthepresentageofsonbex.Thepresentageoftheman=3xAgain,After15years,Theageoftheson=x+15Theageoftheman=3x+15A/Q,2×(Theageofson)=Theageofman=>2(x+15)=3x+15=>2x+30=3x+15=>3x-2x=30-15x=15years.Therefore,Thepresentageofson=15yearsThepresentageofman=3x=3×15=45years.