The man is 3 times as old as his son . After 15 years, he will be only twice as old as his son . Find the present ages. About the author Margaret
Answer: 15 & 45 years Step-by-step explanation: Given: The man is 3 times as old as his son. Let the present age of son be x. The present age of the man = 3x Again, After 15 years, The age of the son = x+15 The age of the man = 3x+15 A/Q, 2×( The age of son) = The age of man => 2(x+15) = 3x+15 => 2x+30 = 3x+15 => 3x-2x = 30-15 x = 15 years. Therefore, The present age of son = 15 years The present age of man = 3x = 3× 15 = 45 years. Reply
Answer:
15 & 45 years
Step-by-step explanation:
Given: The man is 3 times as old as his son.
Let the present age of son be x.
The present age of the man = 3x
Again,
After 15 years,
The age of the son = x+15
The age of the man = 3x+15
A/Q,
2×( The age of son) = The age of man
=> 2(x+15) = 3x+15
=> 2x+30 = 3x+15
=> 3x-2x = 30-15
x = 15 years.
Therefore, The present age of son = 15 years
The present age of man = 3x = 3× 15 = 45 years.