The emf of a cell is balanced at 52 cm length of the potentiometer wire. If 5 ohm resistance is inserted from
the resistance

The emf of a cell is balanced at 52 cm length of the potentiometer wire. If 5 ohm resistance is inserted from
the resistance box connected with the cell, then balancing length obtained is 40 cm The internal resistance of
the cell will be​

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Claire

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  1. Answer:

    1.5 Ω

    Given,

    R=5Ω

    l

    1

    =52cm,l

    2

    =40cm

    To find,

    Internal resistance of cell, r=?

    r=R(

    l

    2

    l

    1

    −1)=5(

    40

    52

    −1)=5(

    40

    52−40

    )=5(

    40

    12

    )=5(

    10

    3

    )=

    10

    15

    =1.5Ω

    ⇒r=1.5Ω

    Therefore, the internal resistance of the cell is 1.5Ω

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