The common difference of an ap is 5/2. What would be the difference of its 15th term and 5th term ?
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Answer:
25
Step-by-step explanation:
AP = a1 , a2 , a3 , a4
AP = a , a+d , a+2d , a+3d
d = 5/2
15th term – a15 = a + 14d
5th term – a5 = a + 4d
a15 – a14
= a + 14d – (a + 4d)
= a + 14d – a 4d
= 14d – 4d
= 10d
= 10 × 5 / 2
= 5 × 5
= 25
∴ the difference of its 15th term and 5th term is 25
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