The common difference of an ap is 5/2. What would be the difference of its 15th term and 5th term ?

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1. Answer:

   25

   Step-by-step explanation:

   AP = a1 , a2 , a3 , a4

   AP = a , a+d , a+2d , a+3d

   d = 5/2

   15th term – a15 = a + 14d

   5th term – a5 = a + 4d

   a15 – a14

   = a + 14d – (a + 4d)

   = a + 14d – a 4d

   = 14d – 4d

   = 10d

   = 10 × 5 / 2

   = 5 × 5

   = 25

   ∴ the difference of its 15th term and 5th term is 25

   ⊕Thank You ⊕

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