The common difference of an ap is 5/2. What would be the difference of its 15th term and 5th term ? About the author Maria

Answer: 25 Step-by-step explanation: AP = a1 , a2 , a3 , a4 AP = a , a+d , a+2d , a+3d d = 5/2 15th term – a15 = a + 14d 5th term – a5 = a + 4d a15 – a14 = a + 14d – (a + 4d) = a + 14d – a 4d = 14d – 4d = 10d = 10 × 5 / 2 = 5 × 5 = 25 ∴ the difference of its 15th term and 5th term is 25 ⊕Thank You ⊕ Reply

Answer:25Step-by-step explanation:AP = a1 , a2 , a3 , a4

AP = a , a+d , a+2d , a+3d

d = 5/2

15th term – a15 = a + 14d

5th term – a5 = a + 4d

a15 – a14

= a + 14d – (a + 4d)

= a + 14d – a 4d

= 14d – 4d

= 10d

= 10 × 5 / 2

= 5 × 5

= 25

∴ the difference of its 15th term and 5th term is 25Thank You⊕