2 thoughts on “a train travelling at 72km/h crosses a man in 20second . find the length of train. pls answer ”
Answer
Speed of the train in metres/sec = 72000/3600 = 20
Speed of the train in metres/sec = 72000/3600 = 20Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platform
Speed of the train in metres/sec = 72000/3600 = 20Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platformDistance travelled by train to cross the man = 18 * 20 = 360 = Length of train
Speed of the train in metres/sec = 72000/3600 = 20Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platformDistance travelled by train to cross the man = 18 * 20 = 360 = Length of trainLength of platform = 600 – 360 = 240
Answer
Speed of the train in metres/sec = 72000/3600 = 20
Speed of the train in metres/sec = 72000/3600 = 20Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platform
Speed of the train in metres/sec = 72000/3600 = 20Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platformDistance travelled by train to cross the man = 18 * 20 = 360 = Length of train
Speed of the train in metres/sec = 72000/3600 = 20Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platformDistance travelled by train to cross the man = 18 * 20 = 360 = Length of trainLength of platform = 600 – 360 = 240
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Answer:
400 m.
Step-by-step explanation:
When trains cross pole or man, distance = length of train.
Given:
Speed = 72 km/h = 72 × 5/18 = 4 × 5 = 20 m/s
Time = 20 s
Distance = Length = Speed × Time = 20 × 20 = 400 m.
Therefore the length of train is 400 m.