[tex]Let \: the \: other \: integer \: be \: x.[/tex] [tex] – 5 + x = \frac{ – 4}{3} [/tex] [tex]x = \frac{ – 4}{3} + 5[/tex] [tex]x = \frac{ – 4}{3} + \frac{5}{1} \times \frac{3}{3} [/tex] [tex]x = \frac{ – 4 + 15}{3} [/tex] [tex]x = \frac{11}{3} [/tex] [tex]Start \: following \: me. \: If \: this \: answer \: is \: \\ helpful \: so \: mark \: my \: answer \: as \\ \: brainliest \: answer.[/tex] Reply
Answer: your answer is -11/3 Step-by-step explanation: according to the question we get let the other number be x [tex]\frac{-5}{1} + x = \frac{-4}{3}[/tex] [tex]x = \frac{-4}{3} – \frac{-5}{1}[/tex] [tex]x= \frac{-4 – (-15)}{3}[/tex] taking lcm [tex]x = \frac{-4 + 15}{3}[/tex] (-) + (-) = (+) [tex]x = \frac{-11}{3}[/tex] Hope it helps you Reply
[tex]Let \: the \: other \: integer \: be \: x.[/tex]
[tex] – 5 + x = \frac{ – 4}{3} [/tex]
[tex]x = \frac{ – 4}{3} + 5[/tex]
[tex]x = \frac{ – 4}{3} + \frac{5}{1} \times \frac{3}{3} [/tex]
[tex]x = \frac{ – 4 + 15}{3} [/tex]
[tex]x = \frac{11}{3} [/tex]
[tex]Start \: following \: me. \: If \: this \: answer \: is \: \\ helpful \: so \: mark \: my \: answer \: as \\ \: brainliest \: answer.[/tex]
Answer:
your answer is -11/3
Step-by-step explanation:
according to the question we get
let the other number be x
[tex]\frac{-5}{1} + x = \frac{-4}{3}[/tex]
[tex]x = \frac{-4}{3} – \frac{-5}{1}[/tex]
[tex]x= \frac{-4 – (-15)}{3}[/tex] taking lcm
[tex]x = \frac{-4 + 15}{3}[/tex] (-) + (-) = (+)
[tex]x = \frac{-11}{3}[/tex]
Hope it helps you