prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal​

2 thoughts on “prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal​”

1. Answer:

   Step-by-step explanation:

   If the radius of two circles is equal then they are called congruent.
   

   So in given figure
   

   In triangle ABO & PQO
   

   OA=OP(radii)
   

   Angle AOB=Angle POQ(given)
   

   OB=OQ(radii)
   

   By SAS
   

   Triangle ABO Is congruent to PQO
   

   By CPCT
   

   AB=PQ
   

   Hence, proved.

   #Pari here…

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2. [tex]\huge\purple{ѕσℓυтîση}[/tex]

   If the radius of the two circles is equal then they are congruent.

   So in the given figure,

   In triangle ABO & PQO

   OA = OP (radii)

   Angle AOB = Angle POQ (given)

   OB = OQ (radii)

   By SAS

   Triangle ABO is congruent to PQO

   By CPCT

   AB = PQ

   Hence, Proved

   hope it’s help you

   Reply