prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal About the author Adalynn

Answer: Step-by-step explanation: If the radius of two circles is equal then they are called congruent. So in given figure In triangle ABO & PQO OA=OP(radii) Angle AOB=Angle POQ(given) OB=OQ(radii) By SAS Triangle ABO Is congruent to PQO By CPCT AB=PQ Hence, proved. #Pari here… Reply

[tex]\huge\purple{ѕσℓυтîση}[/tex] If the radius of the two circles is equal then they are congruent. So in the given figure, In triangle ABO & PQO OA = OP (radii) Angle AOB = Angle POQ (given) OB = OQ (radii) By SAS Triangle ABO is congruent to PQO By CPCT AB = PQ Hence, Proved hope it’s help you Reply

Answer:Step-by-step explanation:If the radius of two circles is equal then they are called congruent.

So in given figure

In triangle ABO & PQO

OA=OP(radii)

Angle AOB=Angle POQ(given)

OB=OQ(radii)

By SAS

Triangle ABO Is congruent to PQO

By CPCT

AB=PQ

Hence, proved.#Pari here…[tex]\huge\purple{ѕσℓυтîση}[/tex]

Iftheradiusofthetwocirclesisequalthentheyarecongruent.Sointhegivenfigure,IntriangleABO&PQOOA=OP(radii)AngleAOB=AnglePOQ(given)OB=OQ(radii)BySASTriangleABOiscongruenttoPQOByCPCTAB=PQHence,Provedhopeit’shelpyou