prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal​

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prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal​

2 thoughts on “prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal​”

  1. Answer:

    Step-by-step explanation:

    If the radius of two circles is equal then they are called congruent.

    So in given figure

    In triangle ABO & PQO

    OA=OP(radii)

    Angle AOB=Angle POQ(given)

    OB=OQ(radii)

    By SAS

    Triangle ABO Is congruent to PQO

    By CPCT

    AB=PQ

    Hence, proved.

    #Pari here…

  2. [tex]\huge\purple{ѕσℓυтîση}[/tex]

    If the radius of the two circles is equal then they are congruent.

    So in the given figure,

    In triangle ABO & PQO

    OA = OP (radii)

    Angle AOB = Angle POQ (given)

    OB = OQ (radii)

    By SAS

    Triangle ABO is congruent to PQO

    By CPCT

    AB = PQ

    Hence, Proved

    hope it’s help you

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