prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal

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Answer:Step-by-step explanation:If the radius of two circles is equal then they are called congruent.

So in given figure

In triangle ABO & PQO

OA=OP(radii)

Angle AOB=Angle POQ(given)

OB=OQ(radii)

By SAS

Triangle ABO Is congruent to PQO

By CPCT

AB=PQ

Hence, proved.#Pari here…[tex]\huge\purple{ѕσℓυтîση}[/tex]

Iftheradiusofthetwocirclesisequalthentheyarecongruent.Sointhegivenfigure,IntriangleABO&PQOOA=OP(radii)AngleAOB=AnglePOQ(given)OB=OQ(radii)BySASTriangleABOiscongruenttoPQOByCPCTAB=PQHence,Provedhopeit’shelpyou