$
Cos (A-A) cot (1 + A) cos (-A)
Z COSA
tan Cata) tan ish &A) sin 125-A)
$
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$
Cos (A-A) cot (1 + A) cos (-A)
Z COSA
tan Cata) tan ish &A) sin 125-A)
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Answer:
tan
2
2
α
cot
−1
(
cosα
)−tan
−1
(
cosα
)=x
2
π
−tan
−1
(
cosα
)−tan
−1
(
cosα
)=x (because cot
−1
x+tan
−1
x=
2
π
)
⇒
2
π
−2tan
−1
(
cosα
)=x
⇒sinx=sin(
2
π
−2tan
−1
(
cosα
))
Let’s say tan
−1
(
cosα
)=θ
⇒tanθ=
cosα
sinx=sin(
2
π
−2θ)=cos2θ
=
1+tan
2
θ
1−tan
2
θ
=
1+cosα
1−cosα
sinx=
1+cosα
1−cosα
=
2cos
2
α/2
2sin
2
α/2
⇒sinx=tan
2
2
α
.
Step-by-step explanation:
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