Isha walks 9 m east and tem 12 m north . how for is she away from her initial point​

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Isha walks 9 m east and tem 12 m north . how for is she away from her initial point​

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  1. Answer:

    By Pythagoras Theorem,

    base² + perpendicular² = hypotenuse²

    9² +12² = hypotenuse²

    81 + 144 = hypotenuse²

    225 = hypotenuse²

    √225 = hypotenuse

    25 = hypotenuse

    Now,

    We can say that she is 15m away from her initial position  

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