in triangle ABC angle B =90°.BD perpendicular to AC. if AB=6cm BC=8cm find AD, DC and BD About the author Kennedy
Answer: In triangle ABC , angle B = 90 degree By using Pythagorus Thearom (AC)*2 = ( AB)*2 + (BC)*2 (AC)*2 = (6)*2 + (8)*2 (AC)*2 = 36 + 64 (AC)*2 = 100 AC = [tex] \sqrt{100} [/tex] AC = 10 AD = DC. ........(1) AC = 2AD 10 =2AD 10/2 = AD 5 = AD DC = 5 cm. from eq. (1) In this way, you can get further solution Reply
Answer:
In triangle ABC , angle B = 90 degree
By using Pythagorus Thearom
(AC)*2 = ( AB)*2 + (BC)*2
(AC)*2 = (6)*2 + (8)*2
(AC)*2 = 36 + 64
(AC)*2 = 100
AC =
[tex] \sqrt{100} [/tex]
AC = 10
AD = DC. ........(1)
AC = 2AD
10 =2AD
10/2 = AD
5 = AD
DC = 5 cm. from eq. (1)
In this way, you can get further solution