Answer: XZ=8CM Step-by-step explanation: as per the given information it is prove that the above Triangle is 30°60° 90° Triangle by 30-60-90 theorem, s side \: opposite \: to \: 30 = \frac{1}{2} \times hypotenusesideoppositeto30= 2 1 ×hypotenuse XY=½XZ XZ=2×XY XZ=2×4 XZ=8 cm Reply

Answer: In right angled triangle yxz (angle x=90°) :- (xy)^2+(xz)^2= (yz)^2. or. (9)^2+(xz)^2=(12)^2. or. (xz)^2= 144–81=63. Or. xz = 3√7 cm. Area of right angled triangle yxz= 1/2. (xy)×(xz)………………….(1) Also area of right angled triangle yxz = 1/2.(ox)×(yz)………………………(2). from eqn. (1) and (2) 1/2.(ox)×(yz) =1/2.(xy)×(xz). or. ox = (xy)×(xz)/(yz). = (9×3√7)/(12) = 9√7/4= 5.95 cms. Answer. Reply

Answer:XZ=8CM

Step-by-step explanation:

as per the given information it is prove that the above Triangle is 30°60° 90° Triangle

by 30-60-90 theorem,

s

side \: opposite \: to \: 30 = \frac{1}{2} \times hypotenusesideoppositeto30=

2

1

×hypotenuse

XY=½XZ

XZ=2×XY

XZ=2×4

XZ=8 cm

Answer:In right angled triangle yxz (angle x=90°) :- (xy)^2+(xz)^2= (yz)^2.

or. (9)^2+(xz)^2=(12)^2.

or. (xz)^2= 144–81=63.

Or. xz = 3√7 cm.

Area of right angled triangle yxz= 1/2. (xy)×(xz)………………….(1)

Also area of right angled triangle yxz = 1/2.(ox)×(yz)………………………(2).

from eqn. (1) and (2)

1/2.(ox)×(yz) =1/2.(xy)×(xz).

or. ox = (xy)×(xz)/(yz). = (9×3√7)/(12) = 9√7/4= 5.95 cms. Answer.