In ∆XYZ , X Y = 90° YZX= 30 and YXZ=60°
seg XY = 4 cm
the find seg XZ​

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In ∆XYZ , X Y = 90° YZX= 30 and YXZ=60°
seg XY = 4 cm
the find seg XZ​

2 thoughts on “In ∆XYZ , X Y = 90° YZX= 30 and YXZ=60°<br />seg XY = 4 cm<br />the find seg XZ​”

  1. Answer:

    XZ=8CM

    Step-by-step explanation:

    as per the given information it is prove that the above Triangle is 30°60° 90° Triangle

    by 30-60-90 theorem,

    s

    side \: opposite \: to \: 30 = \frac{1}{2} \times hypotenusesideoppositeto30=

    2

    1

    ×hypotenuse

    XY=½XZ

    XZ=2×XY

    XZ=2×4

    XZ=8 cm

  2. Answer:

    In right angled triangle yxz (angle x=90°) :- (xy)^2+(xz)^2= (yz)^2.

    or. (9)^2+(xz)^2=(12)^2.

    or. (xz)^2= 144–81=63.

    Or. xz = 3√7 cm.

    Area of right angled triangle yxz= 1/2. (xy)×(xz)………………….(1)

    Also area of right angled triangle yxz = 1/2.(ox)×(yz)………………………(2).

    from eqn. (1) and (2)

    1/2.(ox)×(yz) =1/2.(xy)×(xz).

    or. ox = (xy)×(xz)/(yz). = (9×3√7)/(12) = 9√7/4= 5.95 cms. Answer.

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