In ∆XYZ , X Y = 90° YZX= 30 and YXZ=60°
seg XY = 4 cm
the find seg XZ​

2 thoughts on “In ∆XYZ , X Y = 90° YZX= 30 and YXZ=60°<br />seg XY = 4 cm<br />the find seg XZ​”

1. Answer:

   XZ=8CM

   Step-by-step explanation:

   as per the given information it is prove that the above Triangle is 30°60° 90° Triangle

   by 30-60-90 theorem,

   s

   side \: opposite \: to \: 30 = \frac{1}{2} \times hypotenusesideoppositeto30=

   2

   1

   ×hypotenuse

   XY=½XZ

   XZ=2×XY

   XZ=2×4

   XZ=8 cm

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2. Answer:

   In right angled triangle yxz (angle x=90°) :- (xy)^2+(xz)^2= (yz)^2.

   or. (9)^2+(xz)^2=(12)^2.

   or. (xz)^2= 144–81=63.

   Or. xz = 3√7 cm.

   Area of right angled triangle yxz= 1/2. (xy)×(xz)………………….(1)

   Also area of right angled triangle yxz = 1/2.(ox)×(yz)………………………(2).

   from eqn. (1) and (2)

   1/2.(ox)×(yz) =1/2.(xy)×(xz).

   or. ox = (xy)×(xz)/(yz). = (9×3√7)/(12) = 9√7/4= 5.95 cms. Answer.

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