In an isosceles triangle PQR with PQ = PR, D and E are the points on QR, such that QE= RD, show that PD=PE​

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1. We have,

   According to given figure.

   PQ=PR(giventhat)

   QS=SR(Bydefinationofmidpoint)

   PS=PS(Commonline)

   Then,

   ΔSPQ≅ΔSPR (BY congruency S.S.S.)

   Hence, PS bisects ∠PQR by definition of angle bisector.

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