If ∆ is an operation such that for integers a and b we have,

a ∆ b = a×b–2×a×b+b×b(–a)×b+b×b

Then find (–7) ∆ (–1)

(a) –4

(b) –6

(c) –3

(d) –2

a ∆ b = a×b–2×a×b+b×b(–a)×b+b×b

Then find (–7) ∆ (–1)

If ∆ is an operation such that for integers a and b we have,

a ∆ b = a×b–2×a×b+b×b(–a)×b+b×b

Then find (–7) ∆ (–1)

(a) –4

(b) –6

(c) –3

(d) –2

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Best answer (i) 4 ∆ (–3) = 21, (–3) ∆ 4 = 28, No (ii) (–7) ∆ (–1) = –6, (–1) ∆ (–7) = 42,