If ∆ is an operation such that for integers a and b we have,a ∆ b = a×b–2×a×b+b×b(–a)×b+b×bThen find (–7) ∆ (–1) (a) –4 (b) –6 (c) –3 (d) –2 About the author Alice

Best answer (i) 4 ∆ (–3) = 21, (–3) ∆ 4 = 28, No (ii) (–7) ∆ (–1) = –6, (–1) ∆ (–7) = 42,