If ∆ is an operation such that for integers a and b we have,
a ∆ b = a×b–2×a×b+b×b(–a)×b+b×b
Then find (–7) ∆ (–1)

Question

If ∆ is an operation such that for integers a and b we have, a ∆ b = a×b–2×a×b+b×b(–a)×b+b×b Then find (–7) ∆ (–1)  (a) –4  (b) –6  (c) –3  (d) –2​

Josie · Answer

Best answer (i) 4 ∆ (–3) = 21, (–3) ∆ 4 = 28, No (ii) (–7) ∆ (–1) = –6, (–1) ∆ (–7) = 42,

If ∆ is an operation such that for integers a and b we have,a ∆ b = a×b–2×a×b+b×b(–a)×b+b×bThen find (–7) ∆ (–1)