distance between poit (-4,5) and (12,p) is 10unit find the value of p​

1 thought on “distance between poit (-4,5) and (12,p) is 10unit find the value of p​”

1. Step-by-step explanation:

   (x1,y1)=(-4,5) (x2,y2)=(12,p)

   d=√(x2-x1)^2+(y2-y1)^2

   10=√(12-[-4])^2+(p-5)^2

   10=√(16)^2+(p-5)^2

   10=√256+p^2-25

   10=√231+p^2

   10=15.19+p

   p=10-15.19

   p= -5.19

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