ABCD is a quadrilateral.AO And BO are the angle bisectors of angle A And B which meet at O.IF angle C=70°,angle D=50°,find angle AOBpls with solve About the author Katherine
[tex]\Huge{\textbf{\textsf{{\color{navy}{Quê}}{\purple{sTi}}{\pink{øN}}{\color{pink}{:}}}}}[/tex] ABCD is a quadrilateral. AO And BO are the angle bisectors of angle A and B which meet at O. If angle C=70°, angle D=50°, find angle AOB. [tex]\Huge{\textbf{\textsf{{\color{navy}{Aň}}{\purple{sW}}{\pink{ĕR}}{\color{pink}{:}}}}}[/tex] ĞIVĔN:– ● ABCD is a quadrilateral ● AO And BO are the angle bisectors of angle A and B which meet at O ● ∠C = 70° and ∠D = 50° TØ FINĐ:– ● ∠AOB ŠØLUŤION:– ∠A + ∠B + ∠C + ∠D = 360° let ∠A and ∠B be x so, ⇒ x + x + 70° + 50° = 360° ⇒ 2x + 120° = 360° ⇒ 2x = 360 – 120 ⇒ x = 240/2 ⇒ x = 120° AO And BO are the angle bisectors of angle A and B so, ∠A = 120/2 = 60° ∠B = 120/2 = 60° Now, In triangle AOB, ⇒ ∠AOB + ∠OAB + ∠OBA = 180° ⇒ ∠AOB + 60° + 60° = 180° ⇒ ∠AOB + 120° = 180° ⇒ ∠AOB = 180 – 120 ⇒ ∠AOB = 60° Hence, ∠AOB = 60° #NAWABZAADI Reply
Answer: We have, ABCD is a quadrilateral. Given that, C = 70^o, D = 50^o So, A + B + C + D = 360^o ( A + B ) = 360^o – ( C + D ) ( A + B ) = 360^o – … Reply
[tex]\Huge{\textbf{\textsf{{\color{navy}{Quê}}{\purple{sTi}}{\pink{øN}}{\color{pink}{:}}}}}[/tex]
ABCD is a quadrilateral. AO And BO are the angle bisectors of angle A and B which meet at O. If angle C=70°, angle D=50°, find angle AOB.
[tex]\Huge{\textbf{\textsf{{\color{navy}{Aň}}{\purple{sW}}{\pink{ĕR}}{\color{pink}{:}}}}}[/tex]
ĞIVĔN:–
● ABCD is a quadrilateral
● AO And BO are the angle bisectors of angle A and B which meet at O
● ∠C = 70° and ∠D = 50°
TØ FINĐ:–
● ∠AOB
ŠØLUŤION:–
∠A + ∠B + ∠C + ∠D = 360°
let ∠A and ∠B be x
so,
⇒ x + x + 70° + 50° = 360°
⇒ 2x + 120° = 360°
⇒ 2x = 360 – 120
⇒ x = 240/2
⇒ x = 120°
AO And BO are the angle bisectors of angle A and B
so,
∠A = 120/2 = 60°
∠B = 120/2 = 60°
Now,
In triangle AOB,
⇒ ∠AOB + ∠OAB + ∠OBA = 180°
⇒ ∠AOB + 60° + 60° = 180°
⇒ ∠AOB + 120° = 180°
⇒ ∠AOB = 180 – 120
⇒ ∠AOB = 60°
Hence, ∠AOB = 60°
#NAWABZAADI
Answer:
We have, ABCD is a quadrilateral. Given that, C = 70^o, D = 50^o So, A + B + C + D = 360^o ( A + B ) = 360^o – ( C + D ) ( A + B ) = 360^o – …