ABCD is a quadrilateral.AO And BO are the angle bisectors of angle A And B which meet at O.IF angle C=70°,angle D=50°,find angle A

ABCD is a quadrilateral.AO And BO are the angle bisectors of angle A And B which meet at O.IF angle C=70°,angle D=50°,find angle AOBpls with solve​

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2 thoughts on “ABCD is a quadrilateral.AO And BO are the angle bisectors of angle A And B which meet at O.IF angle C=70°,angle D=50°,find angle A”

  1. [tex]\Huge{\textbf{\textsf{{\color{navy}{Quê}}{\purple{sTi}}{\pink{øN}}{\color{pink}{:}}}}}[/tex]

    ABCD is a quadrilateral. AO And BO are the angle bisectors of angle A and B which meet at O. If angle C=70°, angle D=50°, find angle AOB.

    [tex]\Huge{\textbf{\textsf{{\color{navy}{Aň}}{\purple{sW}}{\pink{ĕR}}{\color{pink}{:}}}}}[/tex]

    ĞIVĔN:

    ABCD is a quadrilateral

    AO And BO are the angle bisectors of angle A and B which meet at O

    C = 70° and D = 50°

    FINĐ:

    AOB

    ŠØLUŤION:

    A + B + C + D = 360°

    let A and B be x

    so,

    x + x + 70° + 50° = 360°

    2x + 120° = 360°

    2x = 360 120

    x = 240/2

    x = 120°

    AO And BO are the angle bisectors of angle A and B

    so,

    ∠A = 120/2 = 60°

    B = 120/2 = 60°

    Now,

    In triangle AOB,

    AOB + OAB + OBA = 180°

    AOB + 60° + 60° = 180°

    AOB + 120° = 180°

    AOB = 180 120

    AOB = 60°

    Hence, ∠AOB = 60°

    #NAWABZAADI

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  2. Answer:

    We have, ABCD is a quadrilateral. Given that, C = 70^o, D = 50^o So, A + B + C + D = 360^o ( A + B ) = 360^o – ( C + D ) ( A + B ) = 360^o – …

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