A beam of protons traveling at 1.30 km/s enters a uniform magnetic field, traveling perpendicular to the field. The beam exits the magnetic field, leaving the field in a direction perpendicular to its original direction (the figure (Figure 1)). The beam travels a distance of 1.60 cm while in the field.
What is the magnitude of the magnetic field?
Answer:
a=qvB /m
use formula to find acceleration and then B with that
I guess it helps