A-4.a If a cos theta + b sin theta= 3 & a sin theta -b cos theta = 4 then value of a2 + b2 is(1) 25(2) 14(3) 7 About the author Sophia
Answer: dbo-wpvt-kej j.oin .m.e.et don’t no answer sorry for inconvenience hope this helps mark as brainlest Reply
Step-by-step explanation: ⇒ acosθ+bsinθ=4 — ( 1 ) ⇒ asinθ−bcosθ=3 — ( 2 ) → Now, squaring and adding ( 1 ) and ( 2 ) ∴ (acosθ+bsinθ)2+(asinθ−bcosθ)2=42+32 ⇒ a2cos2θ+2ab.sinθcosθ+b2sin2θ+a2sin2θ−2ab.sinθcosθ+b2cos2θ=16+9 ⇒ a2(sin2θ+cos2θ)+b2(sin2θ+cos2θ)=25 ∴ a2+b2=25 [∵sin2x+cos2x=1] Reply
Answer:
dbo-wpvt-kej
j.oin .m.e.et
don’t no answer sorry
for inconvenience
hope this helps
mark as brainlest
Step-by-step explanation:
⇒ acosθ+bsinθ=4 — ( 1 )
⇒ asinθ−bcosθ=3 — ( 2 )
→ Now, squaring and adding ( 1 ) and ( 2 )
∴ (acosθ+bsinθ)2+(asinθ−bcosθ)2=42+32
⇒ a2cos2θ+2ab.sinθcosθ+b2sin2θ+a2sin2θ−2ab.sinθcosθ+b2cos2θ=16+9
⇒ a2(sin2θ+cos2θ)+b2(sin2θ+cos2θ)=25
∴ a2+b2=25 [∵sin2x+cos2x=1]