after four years the age of father is twice as old as hos son. five years before the father age was 1 years more than triple of his son. find their present ages
1 thought on “after four years the age of father is twice as old as hos son. five years before the father age was 1 years more than triple of hi”
Answer:
Step-by-step explanation:
x + 4 = 2y and x – 5 = 3y + 1. combining the equations we get x + 4 = 2y, x – 5 = 3y + 1
x = 2y – 4 and x = 3y + 6 adding 4 on both sides. x = 2y, x = 3y + 10 which means x = 10y where y represent ages. = 10 + 4 × 2 = 28 which means his father present age is 24 and his age is 10
Answer:
Step-by-step explanation:
x + 4 = 2y and x – 5 = 3y + 1. combining the equations we get x + 4 = 2y, x – 5 = 3y + 1
x = 2y – 4 and x = 3y + 6 adding 4 on both sides. x = 2y, x = 3y + 10 which means x = 10y where y represent ages. = 10 + 4 × 2 = 28 which means his father present age is 24 and his age is 10