2. Check whether the value given in the brackets is a solution to the given equation
or not:
(a) n + 5 = 19 (n = 1)

July 26, 2021

By Ivy

1 thought on “2. Check whether the value given in the brackets is a solution to the given equation<br />or not:<br />(a) n + 5 = 19 (n = 1)<br /”

1. Answer:

   see this is your answer

   Step-by-step explanation:

   (a) Put n = 1 in the equation, we have :
   

   
   

   n + 5 = 15
   

   
   

   or 1 + 5 = 15

   
   

   or 6 \neq 15
   

   
   

   Thus n = 1 is not a solution.
   

   
   

   
   

   (b) Put n = – 2, we have :
   

   
   

   7n + 5 = 19
   

   
   

   or 7(-2) + 5 = – 14 + 5 = – 9 \neq 19.
   

   
   

   So, n = – 2 is not a solution to given equation.
   

   
   

   
   

   (c) Put n = 2, we have :
   

   
   

   7n + 5 = 19
   

   
   

   or 7(2) + 5 = 14 + 5 = 19 = R.H.S
   

   
   

   Thus n = 2 is the solution for the given equation.
   

   
   

   
   

   (d) Put p = 1 , we have :
   

   
   

   4p – 3 = 13
   

   
   

   or 4(1) – 3 = 1 \neq 13 .
   

   
   

   Thus p = 1 is not a solution.
   

   
   

   
   

   (e) Put p = – 4 , we get :
   

   
   

   4p – 3 = 13
   

   
   

   or 4(1) – 3 = 1 \neq 13 .
   

   
   

   Thus p = 1 is not a solution.
   

   
   

   
   

   (f) Put p = 0 , we get :
   

   
   

   4p – 3 = 13
   

   
   

   or 4(0) – 3 = – 3 \neq 13 .
   

   
   

   Thus p = 0 is not a solution.

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