By using remainder theorem. x+1 =0 x= -1. NOW, PUT the value of x in the equation. f(x) =x^3+x^2-3x+2. f(-1)= (–1)3+(–1)2–3×–1+2 f(-1)= –1+1+3+2 f(–1)=5. so, Remainder is 5. please thanks me . and mark me as brainlists. Reply

By using remainder theorem.

x+1 =0

x= -1.

NOW,

PUT the value of x in the equation.

f(x) =x^3+x^2-3x+2.

f(-1)= (

–1)3+(–1)2–3×–1+2f(-1)=

–1+1+3+2f(–1)=5.so,Remainderis5.pleasethanksme.andmarkmeasbrainlists.