By using remainder theorem. x+1 =0 x= -1. NOW, PUT the value of x in the equation. f(x) =x^3+x^2-3x+2. f(-1)= (–1)3+(–1)2–3×–1+2 f(-1)= –1+1+3+2 f(–1)=5. so, Remainder is 5. please thanks me . and mark me as brainlists. Reply
By using remainder theorem.
x+1 =0
x= -1.
NOW,
PUT the value of x in the equation.
f(x) =x^3+x^2-3x+2.
f(-1)= (–1)3+(–1)2–3×–1+2
f(-1)= –1+1+3+2
f(–1)=5.
so,
Remainder is 5.
please thanks me .
and mark me as brainlists.