2 thoughts on “write balanced chemical equation between oxalic acid and sodium hydroxide reaction”
Answer:
H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i) This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).
H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i) This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).
Answer:
H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i) This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).
Answer:
H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i) This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).