Why is the graph of F=1/r^2 made a straight line passing through origin in physics books
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Why is the graph of F=1/r^2 made a straight line passing through origin in physics books
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2 thoughts on “Why is the graph of F=1/r^2 made a straight line passing through origin in physics books<br />✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏<br /><br /><br />kha gii”

  1. Answer:

    Okay, let’s look at it this way: when does a line pas-s through the origin? The line represents possible values of x and y that satisfy the equation.

    So, when a line pas-ses through the origin, it pas-ses through the coordinates (0,0). x = 0, y = 0. So, let’s model this with the equation ax + by + c = 0. Sub in x = 0 and y = 0 to the equation and we find that 0 + 0 + c = 0. Clearly, c = 0.

    So, with this simple explanation, I hope you understand when a line does pas-s through the origin.

    Now, let’s look at when a line doesn’t pas-s through the origin. This is when c is not equal to 0. Hence, when x = 0, y cannot equal 0; c + by = 0, and we know that c is not 0. If y is 0, then we get c = 0… where c is not 0. Ehh. Thus, you can see that a line does not pas-s through the origin when c is not equal to 0 by ehat is hope is a simple explanation. You don’t need to know how to prove it, I presume, but that’s not too hard either.

    i hope it will helps

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