Which term of the progression 19, 18⅕, 17⅖,….is the first negative term.​

1 thought on “Which term of the progression 19, 18⅕, 17⅖,….is the first negative term.​”

1. Answer:

   Here a=19 , d= \(18\frac{1}{5}-\9\)=\(frac){4}{5}\)

   Step-by-step explanation:

   Let the nth term be the first negative. The

   Tn <0>=a+(n-1)*d<0

   =19+(n-1){-4/5}<0

   19-\

   (frac{4}{5}\)n+\(\frac{4}{5}\<0

   =\(\frac{99}{5}\)-\(\frac{4}{5}

   n>\(\frac{99}{5}*\(\frac{4}{5}\)n<0

   n>\(\frac{99}{4}\)=\(24\frac{3}{4}

   n=25

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