When each side of a square is increased by 3m the area become 52 sq. M what is the length of side of the original square

Question

Kinsley · Answer

Answer:   let the original side be X    then new side is (x-3)    and new area is 64 m^2= (X-3)^2    i.e. 64=x2 +9–6x    i.e. x2–6x-55=0    i.e. x2–11x +5x-55=0    i.e. x(x-11)+5(x-11)=0    i.e. (x-11)(x+5)=0    x= 11, -5    so the length can be negative so the answer will be 11.

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