When a die is thrown, find the probability of an event of getting :
(a) a prime number
(b) not a prime number
(c) a number greater than 5
(d) a number not greater than 5
I will mark brainliest who gives first and correct answer with explanation
Probability of getting prime numbers:–
Total number of prime numbers =2,3,5
Total numbers in die=6
Probability =possible outcomes /total number of outcomes.
3/6=1/2
Probability of getting a number which is not prime numbers:-
Total numbers which are not prime number=4,6
Total numbers in a die =6
Probability =Possible outcome / total number of outcomes
2/6=1/3
a number greater than 5 :–
A number which is greater than 5=6
Total numbers in a die
Probability =possible outcomes / total numbers of outcomes
1/6
a number not greater than 5:–
numbers which are not greater than 5=1,2,3,4,5
Total numbers in a die =6
Probability =Possible outcome / total number of outcomes
5/6
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