when a car driver travelling at a speed of 10 m\s applies brakes and brings the car to rest in 20 s, then the retardation will be: A) + 2m\s2B) – 2 m\s2C) – 0.5 m\s2D) + 0.5 m\s2 About the author Autumn

Answer: (D) + 0.5 m/s2 Step-By-Step Explanation: U (initial velocity) = 10 m/s V (final velocity) = 0 m/s t (time taken) = 20s a (acceleration) = (V – U) / t a = 0 – 10 / 20 a = – 0.5 m/s2 Retardation = 0.5 m/s2 Reply

Answer:(D) + 0.5 m/s2Step-By-Step Explanation:

U (initial velocity) = 10 m/s

V (final velocity) = 0 m/s

t (time taken) = 20s

a (acceleration) = (V – U) / t

a = 0 – 10 / 20

a = – 0.5 m/s2

Retardation = 0.5 m/s2