when x³+2x²-kx+4 is “divided” by x-2 the remainder is k. Find the value of constant k.(division)​

1 thought on “when x³+2x²-kx+4 is “divided” by x-2 the remainder is k. Find the value of constant k.(division)​”

1. Answer:

   Correct option is

   A

   6

   When x

   3

   +3x

   2

   −kx+4 is divided by (x−2), the remainder is 2k

   ∴(x

   3

   +3x

   2

   −kx+4)−2 is exactly divisible by (x−2)

   ⇒x=2 will satisfy the expression [x

   3

   +3x

   2

   −kx+4−2k]

   ⇒ (2)

   3

   +3(2)

   2

   −k(2)+4−2k=0

   ⇒ 8+12−2k+4−2k=0

   ⇒24−4k=0

   ⇒ k=

   4

   24

   =6

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