2 thoughts on “What is the latitudinal value of the Tropic of Cancer?<br />”
Answer:
approximately 23°27′ N
Tropic of Cancer, latitude approximately 23°27′ N of the terrestrial Equator. This latitude corresponds to the northernmost declination of the Sun’s ecliptic to the celestial equator.
Answer:
approximately 23°27′ N
Tropic of Cancer, latitude approximately 23°27′ N of the terrestrial Equator. This latitude corresponds to the northernmost declination of the Sun’s ecliptic to the celestial equator.
Answer:
231upon 2 degree latitude