what is the average age of A and B ?The ratio between one-fifth of A’s age one-fourthof B’s age is 1;2 The productоf their age is 20 timesB’s age About the author Liliana
Answer: Let the present age of A be ‘x ‘ years & B be y years. x = y-10 x-y = -10 Four years hence A= (x +10) years Four years hence B = ( y+ 10) years x+10/y+10 = 3/5 5(x+10) = 3(y+10) 5x+50 = 3y + 30 5x-3y = 30–50 5x-3y = -20 ————(2) Multiplying first equation by 3 3x-3y = -30 ————(3) Subtraction (2) – (3) 2x= 10 x = 5 Substituting x= 5 in equation (1) 5= y-10 y= 15 Verification x+10/y+15 = 5+10/15+10 =15/25 = 3/5 Present age of A is 5 years & B is 15 years. Step-by-step explanation: Hope you like it!☺️ Reply
Answer:
Let the present age of A be ‘x ‘ years & B be y years.
x = y-10
x-y = -10
Four years hence A= (x +10) years
Four years hence B = ( y+ 10) years
x+10/y+10 = 3/5
5(x+10) = 3(y+10)
5x+50 = 3y + 30
5x-3y = 30–50
5x-3y = -20 ————(2)
Multiplying first equation by 3
3x-3y = -30 ————(3)
Subtraction (2) – (3)
2x= 10
x = 5
Substituting x= 5 in equation (1)
5= y-10
y= 15
Verification
x+10/y+15
= 5+10/15+10
=15/25
= 3/5
Present age of A is 5 years & B is 15 years.
Step-by-step explanation:
Hope you like it!☺️