. What is the area and perimeter of a rectangle having length of 19 cm and breadth of 10cm?

By Luna

. What is the area and perimeter of a rectangle having length of 19 cm and breadth of 10cm?

About the author
Luna

2 thoughts on “. What is the area and perimeter of a rectangle having length of 19 cm and breadth of 10cm?”

  1. [tex]\huge\fbox\red{Ex}\fbox\pink{pl}\fbox\purple{An}\fbox\green{Na}\fbox\blue{ti}\fbox\orange{oN}[/tex]

    [tex] \Large{\underline{\underline{\sf{Given:}}}}[/tex]

    [tex]\small \mathfrak \blue{Breadth \: of \: rectangle = 1 0 \: cm }[/tex]

    [tex]\small \mathfrak \blue{Length \: of \: rectangle = 19 \: cm }[/tex]

    [tex]\Large{\underline{\underline{\sf{Find:}}}}[/tex]

    [tex] \small \mathfrak \blue{Area \: of \: rectangle }[/tex]

    [tex] \small \mathfrak \blue{Perimeter \: of \: rectangle}[/tex]

    [tex]\Large{\underline{\underline{\sf{Solution:}}}}[/tex]

    [tex] \small \mathfrak \pink{Area \: of \: rectangle = \red{ length × breadth}}[/tex]

    [tex] \longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = \: 19 \: cm \: \times 10cm }[/tex]

    [tex] \longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = \: 190 \: cm { }^{2} }[/tex]

    [tex] \small \mathfrak \pink{Perimeter \: of \: rectangle \: = \red{2 ( length + breadth)}}[/tex]

    [tex] \longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = 2(19cm \: + 10cm) }[/tex]

    [tex] \longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = 38cm \: + 20cm }[/tex]

    [tex]\longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = 58 \: cm}[/tex]

    [tex] \large \mathfrak \green{Therefore}[/tex]

    [tex] \small \mathfrak {Area \: of \: rectangle = 190 \: cm \: {}^{2} }[/tex]

    [tex] \small \mathfrak {Perimeter \: of \: rectangle \: = 58 \: cm}[/tex]

    Reply
  2. Given

    • length 19 cm
    • width 10 cm

    To find

    • area of rectangle
    • perimeter of rectangle

    solution

    area of rectangle l×b

    =19×10

    =190 square cm.

    .

    perimeter of rectangle

    2( l+b)

    2(19+10)

    2(29)

    =58 cm

    hence the perimeter of rectangle is 58 cm

    and area of rectangle is 190 square cm

    Thanks

    Hope its helpful

    Reply

Leave a Reply to Savannah Cancel reply