*What is the amount for Rs. 10000 by compound interest at 8% rate for 2 years?* 1️⃣ ₹ 50002️⃣ ₹ 116643️⃣ ₹ 156644️⃣ ₹ 10664 About the author Quinn
Answer: Amount = Rs. 11664 Step-by-step explanation: Given: Principal amount (P) = Rs. 10000 Rate of interest (r) = 8% Time (n) = 2 years To Find: Amount (A) Formula used: [tex]\implies{\sf{Amount\;(A)=P\Bigg(1+\dfrac{r}{100}\Bigg)^{n}}}[/tex] Put the values in the formula, [tex]\implies{\sf{Amount\;(A)=P\Bigg(1+\dfrac{r}{100}\Bigg)^{n}}}[/tex] [tex]\implies{\sf{Amount\;(A)=10000\Bigg(1+\dfrac{8}{100}\Bigg)^{2}}}[/tex] [tex]\implies{\sf{Amount\;(A)=10000\Bigg(\dfrac{100+8}{100}\Bigg)^{2}}}[/tex] [tex]\implies{\sf{Amount\;(A)=10000\Bigg(\dfrac{108}{100}\Bigg)^{2}}}[/tex] [tex]\implies{\sf{Amount\;(A)=10000\Big(1.08 \Big)^{2}}}[/tex] [tex]\implies{\sf{Amount\;(A)=10000\times 1.08\times 1.08}}[/tex] [tex]\implies{\boxed{\sf{Amount\;(A)=Rs.\;11664}}}[/tex] Reply
Given :– Principal = Rs.10000 Rate = 8% per annum compounded annually . Time = 2 years. To Find :– Amount = ? Solution :– we know that, when rate is compounded annually, Amount = Principal * [1 + (Rate/100)]^ time putting values we get, → Amount = 10000 * [1 + (8/100)]² → Amount = 10000 * [1 + (2/25)]² → Amount = 10000 * (27/25)² → Amount = 10000 * (27 * 27 /25 * 25) → Amount = (10000 * 729) / 625 → Amount = Rs.11664 (Option 2) (Ans.) Learn more :- A sum of money grows 216/125 times when invested for 3 years in shares where interest is computed annually. How long wil… https://brainly.in/question/20712133 A person invest two equal sums, one at simple interest and another at compound interest at same rate for two years. Afte… https://brainly.in/question/27125261 Reply
Answer:
Step-by-step explanation:
Given:
To Find:
Formula used:
[tex]\implies{\sf{Amount\;(A)=P\Bigg(1+\dfrac{r}{100}\Bigg)^{n}}}[/tex]
Put the values in the formula,
[tex]\implies{\sf{Amount\;(A)=P\Bigg(1+\dfrac{r}{100}\Bigg)^{n}}}[/tex]
[tex]\implies{\sf{Amount\;(A)=10000\Bigg(1+\dfrac{8}{100}\Bigg)^{2}}}[/tex]
[tex]\implies{\sf{Amount\;(A)=10000\Bigg(\dfrac{100+8}{100}\Bigg)^{2}}}[/tex]
[tex]\implies{\sf{Amount\;(A)=10000\Bigg(\dfrac{108}{100}\Bigg)^{2}}}[/tex]
[tex]\implies{\sf{Amount\;(A)=10000\Big(1.08 \Big)^{2}}}[/tex]
[tex]\implies{\sf{Amount\;(A)=10000\times 1.08\times 1.08}}[/tex]
[tex]\implies{\boxed{\sf{Amount\;(A)=Rs.\;11664}}}[/tex]
Given :–
To Find :–
Solution :–
we know that, when rate is compounded annually,
putting values we get,
→ Amount = 10000 * [1 + (8/100)]²
→ Amount = 10000 * [1 + (2/25)]²
→ Amount = 10000 * (27/25)²
→ Amount = 10000 * (27 * 27 /25 * 25)
→ Amount = (10000 * 729) / 625
→ Amount = Rs.11664 (Option 2) (Ans.)
Learn more :-
A sum of money grows 216/125 times when invested for 3 years in shares where interest is computed annually. How long wil…
https://brainly.in/question/20712133
A person invest two equal sums, one at simple interest and another at compound interest at same rate for two years. Afte…
https://brainly.in/question/27125261