we have 100 litres of a mixture of milk and water which is 10% water. How much more pure milk should be added so that the new mix

2 thoughts on “we have 100 litres of a mixture of milk and water which is 10% water. How much more pure milk should be added so that the new mix”

1. Answer:

   100 liters pure milk to 100+100 = 200 (milk+water) has 10 liters water. So the percentage of water in the mixture = 10 x 100/200 = 5%. Answer. Add 100 liters of pure milk.

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2. Given:

   • Total Quantity mixture of milk and water = 100
   • Percentage (quantity) of water = 10 %

   To find:

   • How much more pure milk should be added so that the new mixture has only 5% water?

   Solutions:

   Total Quantity of mixture of milk and water = 100 l

   In mixture,Quantity of water = 10 %

   Quantity of Pure milk = ( 100 – 10 ) l = 90 l

   Let ‘x’ be the milk added to the mixture to make water 5 % and pure milk 95 % .

   As per the question,

   [tex](90 + x)l = 95\% \times( 100 + x)l[/tex]

   [tex] = > 90 + x = 0.95(100 + x)[/tex]

   [tex] = > 90 + x = 95 + 0.95x[/tex]

   [tex] = > x – 0.95x = 95 – 90[/tex]

   [tex] = > 0.05x = 5[/tex]

   [tex] = > x = \frac{5}{0.05} = 100l[/tex]

   So, 100l of pure milk should be added so that the new mixture has only 5 % water.

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