Answer: 210 Step-by-step explanation: the series are in ap sum of terms in ap= [tex] \frac{n}{2}(2a+(n-1)d)[/tex] =10/2(2*3+(10-1)4) =5(6+36) =42*5 =210 Reply
Answer: n=10, a=3 ,d=4 Sn = n/2[2a+(n-1)d] S(10) = 10/2[2×3 + (10-1)4] = 5[6+36] = 5×42 = 210 Step-by-step explanation: the sum of first 10 terms of the given series is 210. Reply
Answer:
210
Step-by-step explanation:
the series are in ap
sum of terms in ap=
[tex] \frac{n}{2}(2a+(n-1)d)[/tex]
=10/2(2*3+(10-1)4)
=5(6+36)
=42*5
=210
Answer:
n=10, a=3 ,d=4
Sn = n/2[2a+(n-1)d]
S(10) = 10/2[2×3 + (10-1)4]
= 5[6+36]
= 5×42
= 210
Step-by-step explanation:
the sum of first 10 terms of the given series is 210.