Use velocity- time graph of a particle to prove first and second equation of motion About the author Sophia
Answer: At t = 0, initial velocity = u = OA At t = t, final velocity = v = OC The distance S travelled in time t = area of the trapezium OABD s = (1/2) x (OA + DB) × OD s = (1/2) x (u + v) × t Since v = u + at, s = (1/2) x (u + u + at) × t s = ut + (1/2) at2 Explanation: I request you to please follow my account Reply
Answer:
At t = 0, initial velocity = u = OA
At t = t, final velocity = v = OC
The distance S travelled in time t = area of the trapezium OABD
s = (1/2) x (OA + DB) × OD
s = (1/2) x (u + v) × t
Since v = u + at,
s = (1/2) x (u + u + at) × t
s = ut + (1/2) at2
Explanation:
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