ulina plays both volleyball and soccer. The probability of her getting injured playing volleyball is 0.10.10, point, 1. The probability of her getting injured playing soccer is \dfrac{1}{10}
10
1
start fraction, 1, divided by, 10, end fraction.
Complete question: Paulina plays both volleyball and soccer. The probability of her getting injured playing volleyball is 0.1. The probability of her getting injured playing soccer is 1/10. Which of these events is more likely?
Solution:
‘More likely’ means to have the probability of occurrence of one event more than the other events.
While polling volleyball, probability of getting hurt is
P(A) = 0.1
and in the case of soccer, it is
P(B) = 1/10
i.e., P(B) = 0.1
Here we see, P(A) = P(B)
Answer: We can conclude that no event is more likely to occur than the other, i.e., the probability of occurrence for each event is equally likely.