ua)b) 8C) TUd) 12iv) When 3 is added to length and breadth of rectangle, the perimeter become22. What is the mathematical form of the statement ?a) x + y = 16 b) x+y= 5 c) x + y = -5 d) x + y = 22 About the author Reagan
Answer: Let length be x+3 Let length be x+3and,breadth be y+3 Let length be x+3and,breadth be y+3the perimeter of rectangle Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22 Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then, Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22 Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22x+y+6=11 Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22x+y+6=11x+y=11‐6 Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22x+y+6=11x+y=11‐6x+y=5 Hence it is in the stantance of x+y=5 ( c) Reply
Answer:
Let length be x+3
Let length be x+3and,breadth be y+3
Let length be x+3and,breadth be y+3the perimeter of rectangle
Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22
Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,
Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22
Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22x+y+6=11
Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22x+y+6=11x+y=11‐6
Let length be x+3and,breadth be y+3the perimeter of rectangle =2×(l+b)=22then,2(x+3+y+3)=22x+y+6=11x+y=11‐6x+y=5
Hence it is in the stantance of x+y=5 ( c)