Two sets having identical elements are known asa.null setsb. equal setsC.disjoint setsd. None of the above About the author Evelyn
Solution The required numbers are 1, 2, 3, 4, 5, 6. So, the given set in the roster form is {1, 2, 3, 4, 5, 6}. Example 3 Write the set A = {1, 4, 9, 16, 25, . . . }in set-builder form. Solution We may write the set A as A = {x : x is the square of a natural number} Alternatively, we can write A = {x : x = n2 , where n ∈ N} Example 4 Write the set 123456 { } 234567 ,,,,, in the set-builder form. Solution We see that each member in the given set has the numerator one less than the denominator. Also, the numerator begin from 1 and do not exceed 6. Hence, in the set-builder form the given set is where is a natural number and 1 6 1 n x:x , n n n ⎧ ⎫ ⎨ ⎬ = ≤≤ ⎩ ⎭ + Example 5 Match each of the set on the left described in the roster form with the same set on the right described in the set-builder form : (i) {P, R, I, N, C, A, L} (a) { x : x is a positive integer and is a divisor of 18} (ii) { 0 } (b) { x : x is an integer and x2 – 9 = 0} (iii) {1, 2, 3, 6, 9, 18} (c) {x : x is an integer and x + 1= 1} (iv) {3, –3} (d) {x : x is a letter of the word PRINCIPAL} Solution Since in (d), there are 9 letters in the word PRINCIPAL and two letters P and I are repeated, so (i) matches (d). Similarly, (ii) matches (c) as x + 1 = 1 implies x = 0. Also, 1, 2 ,3, 6, 9, 18 are all divisors of 18 and so (iii) matches (a). Finally, x2 – 9 = 0 implies x = 3, –3 and so (iv) matches (b). EXERCISE 1.1 1. Which of the following are sets ? Justify your answer. (i) The collection of all the months of a year beginning with the letter J. (ii) The collection of ten most talented writers of India. (iii) A team of eleven best-cricket batsmen of the world. (iv) The collection of all boys in your class. (v) The collection of all natural numbers less than 100. (vi) A collection of novels written by the writer Munshi Prem Chand. [tex]hope \: this \: will \: help \: you[/tex] Reply
Option b Step-by-step explanation: Given:– Two sets having identical elements To find:– What type of these sets ? Solution:– Two sets having identical elements then the two sets are called Equal sets . If A and B are having identical elements then both A and B are called equal sets and it is denoted by A=B. That means All elements in A are in B and all elements in B area also in A. Answer:– Two sets having identical elements then the two sets are called Equal sets . Options wise explanation:– Null sets :- A set having no element in it is called a null or void or empty set. Ex:- A is a set of whole numbers less than 0 Dis joint sets:– If two sets having no elements in common then they are called Dis joint sets. If A and B are dis joint sets then AnB = { } n(AnB) = 0. Reply
Solution The required numbers are 1, 2, 3, 4, 5, 6. So, the given set in the roster form
is {1, 2, 3, 4, 5, 6}.
Example 3 Write the set A = {1, 4, 9, 16, 25, . . . }in set-builder form.
Solution We may write the set A as
A = {x : x is the square of a natural number}
Alternatively, we can write
A = {x : x = n2
, where n ∈ N}
Example 4 Write the set
123456 { }
234567
,,,,, in the set-builder form.
Solution We see that each member in the given set has the numerator one less than
the denominator. Also, the numerator begin from 1 and do not exceed 6. Hence, in the
set-builder form the given set is
where is a natural number and 1 6
1
n
x:x , n n
n
⎧ ⎫ ⎨ ⎬ = ≤≤ ⎩ ⎭ +
Example 5 Match each of the set on the left described in the roster form with the
same set on the right described in the set-builder form :
(i) {P, R, I, N, C, A, L} (a) { x : x is a positive integer and is a divisor of 18}
(ii) { 0 } (b) { x : x is an integer and x2 – 9 = 0}
(iii) {1, 2, 3, 6, 9, 18} (c) {x : x is an integer and x + 1= 1}
(iv) {3, –3} (d) {x : x is a letter of the word PRINCIPAL}
Solution Since in (d), there are 9 letters in the word PRINCIPAL and two letters P and I
are repeated, so (i) matches (d). Similarly, (ii) matches (c) as x + 1 = 1 implies
x = 0. Also, 1, 2 ,3, 6, 9, 18 are all divisors of 18 and so (iii) matches (a). Finally, x2 – 9 = 0
implies x = 3, –3 and so (iv) matches (b).
EXERCISE 1.1
1. Which of the following are sets ? Justify your answer.
(i) The collection of all the months of a year beginning with the letter J.
(ii) The collection of ten most talented writers of India.
(iii) A team of eleven best-cricket batsmen of the world.
(iv) The collection of all boys in your class.
(v) The collection of all natural numbers less than 100.
(vi) A collection of novels written by the writer Munshi Prem Chand.
[tex]hope \: this \: will \: help \: you[/tex]
Option b
Step-by-step explanation:
Given:–
Two sets having identical elements
To find:–
What type of these sets ?
Solution:–
Two sets having identical elements then the two sets are called Equal sets .
If A and B are having identical elements then both A and B are called equal sets and it is denoted by A=B.
That means All elements in A are in B and all elements in B area also in A.
Answer:–
Two sets having identical elements then the two sets are called Equal sets .
Options wise explanation:–
Null sets :-
A set having no element in it is called a null or void or empty set.
Ex:-
A is a set of whole numbers less than 0
Dis joint sets:–
If two sets having no elements in common then they are called Dis joint sets.
If A and B are dis joint sets then AnB = { }
n(AnB) = 0.