Contact Style About

To divide line segment AB in the ratio m:n , a ray A X is drawn so that BAX is acute angle and then points are marked on ray AX at

By Lydia

To divide line segment AB in the ratio m:n , a ray A X is drawn so that BAX is acute angle and then points are marked on ray AX at equal distance . Find the minimum of these points​

About the author
Lydia

teams is called Slnomale
4.5 cm
2 solve the following questions,
@ End the perimeter Sf ‘squage whose side is

∆ ABC similar to ∆ pqr A ( ∆ ABC =81 cm2 if AB = 6 cm they find ∆ pqr find the side and perimeter of the square those diagonal is

1 thought on “To divide line segment AB in the ratio m:n , a ray A X is drawn so that BAX is acute angle and then points are marked on ray AX at”

  1. Answer:

    We know that, to divide a line segment AB in the ratio m: n, first draw a ray AX which makes an acute angle ∠BAX, then marked m + n points at equal distance. Here, m = 5, n = 7 So, minimum number of these points = m+n = 5 + 7 = 12. Solution: (a) Given a line segment AB and we have to divide it in the ratio 5:6.

    Step-by-step explanation:

    hope it help u

    Reply

Leave a Reply to Harper Cancel reply