Tina took 2⅓ hours to travel 4 by 9 of the distance between Town A and Town B at an average speed of 72km/h what was Tina’s averag

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1. Answer:

   Tina took 7/3 hours to travel 4/9 distance between Town A and town b.

   speed= 72km/h

   now, she took 4 hours 12 minutes to travel from Town A and Town B.

   find the speed ?

   let the distance = 4/9x

   so, distance= speed × time

   4/9x= 72× 7/3

   4/9x= 24×7/1

   4/9x= 168/1

   4x×1=9×168

   4x=1512

   x= 1512÷4x

   x= 378 km

   then now time = 4hours + 12 minutes

   so, 1 hours = 60 minutes

   4 hours= 4× 60+12=240+12=252 minutes

   then, 1 minutes= 1/60 hours= 252÷60 = 21/5 hours

   now, speed = distance× time

   = 378×5/21

   = 90km/h.r

   hence, when Tina took 4 hours 12 minutes to complete distance town a and town b then speed is 90 km/ h.r

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