three unbaised coins are tosses. whats the probability of getting at most one head​

1 thought on “three unbaised coins are tosses. whats the probability of getting at most one head​”

1. Total no of probabilities=8

   for 1 heads probability is =4

   So we can include HHH, because it contains 0 heads.

   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

   Let E = event of getting at most one heads.

   Then E = {THH, HTH, HHT,HHH}.

   P(E)= n(S)

   n(E) = 4/8=1/2

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