There is number whose double is greater then its half by 45 .Can you find this number

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1. Answer:

   Let the number be x

   According to the question :

   2x=45+ x/2

   2x= (45*2 + x )/2

   Multiplying both sides by 2

   2* 2x= 90+x

   4x=90+x

   Subtracting x from both sides

   4x-x=90

   3x=90

   Dividing both sides by 3

   x=90/3

   x=30

   Verification:

   2x=45+x/2

   2*30=45+30/2

   60=45+15

   60=60

   LHS=RHS

   Hence verified ,the number is 30

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