There is number whose double is greater then its half by 45 .Can you find this number

There is number whose double is greater then its half by 45 .Can you find this number

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  1. Answer:

    Let the number be x

    According to the question :

    2x=45+ x/2

    2x= (45*2 + x )/2

    Multiplying both sides by 2

    2* 2x= 90+x

    4x=90+x

    Subtracting x from both sides

    4x-x=90

    3x=90

    Dividing both sides by 3

    x=90/3

    x=30

    Verification:

    2x=45+x/2

    2*30=45+30/2

    60=45+15

    60=60

    LHS=RHS

    Hence verified ,the number is 30

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